Logical Reasoning
MCQs — 10 Questions
(+2 / -1)
1
sequencing
medium
In a row of 11 kites arranged from left to right as: A B C D E F G H I J K (K is at the right end), kite ___ is fourth to the left of the third kite from the right end.
A
D
B
E
C
F
D
G
Show answer
Answer: B
The third kite from the right end is I (K is 1st from right, J is 2nd, I is 3rd). Fourth to the left of I means 4 positions before it: I, H, G, F, E — that is kite E.
2
shapes
easy
Select the odd one out.
Options A–D show four shapes.
Show answer
Answer: D
Option A (hexagon), B (rectangle) and C (trapezium) are all made up of only straight sides. Option D is an oval, a curved shape with no straight sides, so it is the odd one out.
3
pattern-completion
hard
Which of the following figures will replace the question mark (?) in the given figure so that the pattern is completed?
Options A–D show four candidate squares.
Show answer
Answer: D
Each square is divided into 4 triangles by its diagonals, and one more triangle gets shaded at every step: 1 triangle shaded, then 2, then 3 — so the missing square must have all 4 triangles shaded, which means the whole square is coloured. That matches option D.
4
calendar
medium
If two days ago was Monday, then the 10th day from today will be ____.
A
Friday
B
Saturday
C
Sunday
D
Monday
Show answer
Answer: B
Two days ago was Monday, so today is Wednesday. Adding 10 days: 10 ÷ 7 leaves a remainder of 3, so the 10th day from Wednesday is the same as 3 days after Wednesday — Thursday, Friday, Saturday. So it is Saturday.
5
anagram
easy
Arrange the letters given below to form a meaningful English word and identify the category of that word.
A M N G O
A
Animal
B
Fruit
C
Flower
D
Month
Show answer
Answer: B
The letters A, M, N, G, O rearrange to form MANGO, which belongs to the category Fruit.
6
shapes
medium
The given figure is made up of only three different types of shapes. Which of the following shapes is missing in the given figure?
A
Circle
B
Rectangle
C
Square
D
Triangle
Show answer
Answer: A
The figure is built from a triangle (antenna), a square (head), and rectangles (body, arms and legs). No circle is used anywhere in the figure, so it is the missing shape.
7
mirror-image
medium
Select the CORRECT mirror image of the given figure.
Options A–D show four candidate figures.
Show answer
Answer: A
A mirror image simply flips the figure left-to-right, keeping the same vertical position. Option A shows the arrow pointing left in the same orientation. Option B is the unchanged original, option C is a 180° rotation (not a mirror), and option D is a completely different, unrelated shape.
8
figure-matrix
hard
The given figure matrix follows two rules together — the number of sides of the outer shape, and which shape (if any) is nested inside it. Which of the following figures will replace the question mark (?)?
Options A–D show four candidate shapes.
Show answer
Answer: A
The outer shape's sides increase by 1 at each step: triangle (3) alone, square (4) with a triangle nested inside, pentagon (5) with a square nested inside. Each cell's inner shape is the previous cell's outer shape. So the missing outer shape must be a hexagon (6 sides) with a pentagon nested inside it — option A. Option B is a heptagon alone (wrong side count and no nesting), option C is a hexagon alone (missing the nested pentagon), and option D repeats the pentagon-with-square combination from the third cell.
9
spatial-reasoning
medium
The given figure shows a network of one-way paths (arrows) connecting a cat to a bowl of milk through some junction points. Moving only in the direction the arrows point, in how many different ways can the cat reach the bowl of milk?
A
3
B
4
C
5
D
6
Show answer
Answer: B
From the cat, the arrows split into two junctions. Tracing every route to the bowl: Cat→top junction→top-most dot→Bowl, Cat→top junction→middle dot→Bowl, Cat→bottom junction→middle dot→Bowl, and Cat→bottom junction→bottom-most dot→Bowl. That gives 4 different routes in total.
10
spatial-reasoning
medium
Select the figure from the options which is exactly embedded in the given figure as one of its parts.
Options A–D show four candidate shapes.
Show answer
Answer: A
The middle section of the zigzag line (the 3-segment 'W' shape between the second and third bends) matches option A exactly. Option B is its mirror image, option C is the same shape stretched taller, and option D has completely different angles — none of these appear in the given figure.
Mathematical Reasoning
MCQs — 10 Questions
(+2 / -1)
11
place-value
medium
Which of the following abacuses shows a number more than 3421?
Options A–D show four abacuses.
Show answer
Answer: C
Option A shows 3164, option B shows 3421 (equal, not more), option C shows 3652, and option D shows 3399. Only 3652 is more than 3421.
12
fractions
medium
Compare the following and fill in the box using >, < or =.
4/19 + 6/19 + 3/19 ___ 25/19 − 14/19
A
>
B
=
C
<
D
Can't be determined
Show answer
Answer: A
4/19 + 6/19 + 3/19 = 13/19. 25/19 − 14/19 = 11/19. Since 13/19 is greater than 11/19, the correct symbol is >.
13
money
medium
Meera has a ₹500 note, a ₹100 note, a ₹50 note and a ₹20 note in her purse. Which of the following items can she buy with that money?
A
A toy priced at ₹725
B
A book priced at ₹690
C
A bag priced at ₹650
D
None of these
Show answer
Answer: C
Meera has 500 + 100 + 50 + 20 = ₹670 in total. Of the listed prices, only the ₹650 bag costs less than or equal to ₹670, so she can buy the bag.
14
time
medium
A cooking show starts at 6:40 p.m. and lasts for 1 hour 35 minutes. Which of the following clocks shows the time at which the show ends?
Options A–D show four clocks.
Show answer
Answer: A
6:40 p.m. + 1 hour 35 minutes = 8:15 p.m. (6:40 + 1:20 = 8:00, plus the remaining 15 minutes = 8:15). Option A shows 8:15.
15
perimeter
hard
If the total length of the boundary of the given figure (not drawn to scale) is 44 cm, then find the value of X.
A
10
B
8
C
12
D
14
Show answer
Answer: A
Perimeter = sum of all sides. Adding the given sides: 6 + 5 + 4 + 7 + 12 = 34 cm. So X = 44 − 34 = 10 cm.
16
fractions
medium
The given figure shows four shapes with some parts shaded. Which two figures have equal shaded fractions?
A
1 and 3, 2 and 4
B
1 and 2, 3 and 4
C
1 and 4, 2 and 3
D
None of these
Show answer
Answer: A
Figure 1 (square) has 2 of 4 equal parts shaded = 1/2. Figure 3 (circle) has 2 of 4 equal sectors shaded = 1/2. Figure 2 (triangle) has 1 of 4 equal parts shaded = 1/4. Figure 4 (circle) has 1 of 4 equal sectors shaded = 1/4. So figures 1 & 3 match (1/2 each), and figures 2 & 4 match (1/4 each).
17
data-handling
medium
The given pictograph shows the number of pencils arranged by Ira in six different rows of a drawer. Study it carefully.
In which two rows was the same number of pencils arranged?
A
Row 1 and Row 6
B
Row 2 and Row 4
C
Row 3 and Row 6
D
Row 1 and Row 5
Show answer
Answer: B
Row 2 has 9 pencil icons and Row 4 also has 9 pencil icons (45 pencils each), so these two rows are equal.
18
data-handling
medium
Using the same pictograph as the previous question, how many more pencils were arranged in Rows 1 and 5 together than in Row 3?
A
35
B
40
C
45
D
50
Show answer
Answer: C
Row 1 = 6 × 5 = 30 pencils, Row 5 = 7 × 5 = 35 pencils, together = 65. Row 3 = 4 × 5 = 20 pencils. Difference = 65 − 20 = 45.
19
measurement
medium
The length of the paintbrush is ___ units longer than the crayon shown. (Here, 1 ▭ = 4 units.)
A
12
B
16
C
20
D
8
Show answer
Answer: A
The paintbrush spans 8 boxes and the crayon spans 5 boxes, a difference of 3 boxes. Since 1 box = 4 units, the paintbrush is 3 × 4 = 12 units longer.
20
number-sense
medium
A 3-digit number is multiplied by a 1-digit number. The maximum number of digits in the product is ____.
A
3
B
4
C
5
D
6
Show answer
Answer: B
The largest possible 3-digit number is 999 and the largest 1-digit number is 9. Their product, 999 × 9 = 8991, has 4 digits — the maximum possible.
Everyday Mathematics
MCQs — 10 Questions
(+4)
21
money
easy
A washing machine costs ₹18,600. A microwave costs ₹6,200 less than the washing machine. How much do both items cost together?
A
₹24,800
B
₹31,000
C
₹36,800
D
₹12,400
Show answer
Answer: B
Microwave = 18,600 − 6,200 = ₹12,400. Together = 18,600 + 12,400 = ₹31,000.
22
weight
medium
The weight of 3 dozen oranges is 5 kg 400 g. If each orange weighs the same, then the weight of 5 oranges is ____.
A
600 g
B
650 g
C
700 g
D
750 g
Show answer
Answer: D
3 dozen = 36 oranges weigh 5,400 g, so each orange weighs 5,400 ÷ 36 = 150 g. So 5 oranges weigh 5 × 150 = 750 g.
23
division
easy
At a wedding, 342 guests were seated in 9 rows with an equal number of guests in each row. How many guests were there in each row?
A
36
B
38
C
40
D
42
Show answer
Answer: B
342 ÷ 9 = 38 guests in each row.
24
fractions
medium
Priya cut a cake into 20 equal pieces. She gave 3 pieces to each of her 3 cousins and ate 2 pieces herself. What fraction of the cake is left with her?
A
9/20
B
11/20
C
3/20
D
7/20
Show answer
Answer: A
Pieces given away = 3 × 3 = 9, plus 2 eaten = 11 pieces used. Left = 20 − 11 = 9 pieces, which is 9/20 of the cake.
25
time
easy
Neha's dance class was scheduled at 4:00 p.m. but got delayed and started after 25 minutes. If the class ended at 5:10 p.m., then how long was the class?
A
40 minutes
B
45 minutes
C
50 minutes
D
65 minutes
Show answer
Answer: B
The class started at 4:00 + 25 minutes = 4:25 p.m. and ended at 5:10 p.m., a duration of 45 minutes.
26
perimeter
medium
Tanya and her three friends jogged around a rectangular park at the same time. If the length and breadth of the park are 25 m and 15 m respectively, then find the total distance covered by all of them in 1 complete round.
A
80 m
B
160 m
C
240 m
D
320 m
Show answer
Answer: D
Perimeter of the park = 2 × (25 + 15) = 80 m. Tanya and her 3 friends make 4 people in total, so total distance covered = 4 × 80 = 320 m.
27
arithmetic
medium
Karan has 4,236 marbles. He divides them equally between his brother and himself. If his brother then lost 618 marbles, how many marbles are left with the brother?
A
1,500
B
1,618
C
2,118
D
3,618
Show answer
Answer: A
Each share = 4,236 ÷ 2 = 2,118 marbles. After losing 618, the brother is left with 2,118 − 618 = 1,500 marbles.
28
fractions
easy
A squirrel was given 18 nuts. It ate some nuts and 5 of them were left. Find the fraction of nuts eaten by the squirrel.
A
13/18
B
5/18
C
13/13
D
5/13
Show answer
Answer: A
Nuts eaten = 18 − 5 = 13. Fraction eaten = 13/18.
29
place-value
easy
Ritika formed the largest 4-digit number by using the digits 6, 3, 0 and 8 (each digit only once). The number name of the number formed by her is ____.
A
Eight thousand six hundred and thirty
B
Six thousand eight hundred and thirty
C
Eight thousand three hundred and sixty
D
Eight thousand six hundred and three
Show answer
Answer: A
The largest number from 6, 3, 0, 8 is 8630, whose number name is Eight thousand six hundred and thirty.
30
arithmetic
medium
Aman and his sister together saved ₹6,240 in a month. Aman, his sister and his brother together saved ₹8,410 in that month. How much did Aman's brother save that month?
A
₹1,940
B
₹2,170
C
₹2,410
D
₹1,760
Show answer
Answer: B
Brother's savings = 8,410 − 6,240 = ₹2,170.
Achievers Section
MCQs — 5 Questions
(+5)
31
mixed-reasoning
hard
Which of the following statements is/are CORRECT?
P. A cone has two flat faces.
Q. The difference between the number of faces of a cube and a sphere is 5.
R. The number of triangles in the given figure is 5.
The figure shown is for statement R — a triangle divided into 4 equal parts by joining the midpoints of its sides.
A
Only P
B
Only Q
C
Both P and Q
D
Both Q and R
Show answer
Answer: D
P is false — a cone has only 1 flat face (its circular base) and 1 curved surface, not two flat faces. Q is true — a cube has 6 faces and a sphere has 1 (curved) face, a difference of 5. R is true — joining the midpoints of the triangle's sides creates 4 small triangles, and counting the 4 small ones plus the original big triangle gives 5 triangles in total. So both Q and R are correct.
32
place-value
hard
Observe the given two abacuses carefully and answer the following questions.
(p) The difference between the place value of the digit at hundreds place on abacus Y and the face value of the digit at thousands place on abacus X is ____.
(q) 6 hundreds 3 tens 5 ones more than the number shown on abacus X is ____.
(r) If the number of beads at tens place and ones place on abacus Y got interchanged, then the sum of the new number formed and the original number on abacus Y is ____.
A
(p) 597, (q) 3799, (r) 7255
B
(p) 603, (q) 3789, (r) 7245
C
(p) 597, (q) 3789, (r) 7255
D
(p) 603, (q) 3799, (r) 7245
Show answer
Answer: A
Abacus X shows 3164 and abacus Y shows 3614.
(p) Place value of the hundreds digit on Y (6) = 600. Face value of the thousands digit on X = 3. Difference = 600 − 3 = 597.
(q) 6 hundreds 3 tens 5 ones = 635. 3164 + 635 = 3799.
(r) On Y (3614), the tens digit is 1 and ones digit is 4. Interchanging gives 3641. Sum of new and original = 3641 + 3614 = 7255.
33
measurement
hard
Observe the given balance scales carefully and find the weight of the basket of vegetables.
A
3 kg 800 g
B
4 kg
C
3 kg 600 g
D
None of these
Show answer
Answer: B
From Scale 3, 1 melon = 2,400 g. From Scale 2, 3 mangoes = 1 melon = 2,400 g, so 1 mango = 800 g. From Scale 1, 1 toy car = 2 mangoes = 1,600 g. From Scale 4, the basket = 1 toy car + 1 melon = 1,600 + 2,400 = 4,000 g = 4 kg.
34
fractions
hard
The given figure is divided into 30 equal squares. Some squares are fully shaded, some are shaded along only half (split by a diagonal), and some are shaded along only half (split down the middle into two equal vertical halves). Study the given figure carefully and state T for True and F for False.
(p) The shaded fraction of the given figure is 3/5.
(q) The number of more squares that should be fully shaded so that the given figure has 3/5 as the shaded fraction, is 6.
(r) The difference between the unshaded and shaded fractions of the given figure is 2/5.
A
(p) F, (q) T, (r) F
B
(p) T, (q) T, (r) F
C
(p) F, (q) F, (r) T
D
(p) T, (q) F, (r) T
Show answer
Answer: A
The figure has 30 equal squares: 8 are fully shaded (8 whole units), 4 are diagonally split with one triangle shaded (4 × 0.5 = 2 units), and 4 are split into two vertical halves with one half shaded (4 × 0.5 = 2 units). Total shaded = 8 + 2 + 2 = 12 out of 30, giving a shaded fraction of 12/30 = 2/5, not 3/5 — so (p) is False.
To reach a shaded fraction of 3/5, the shaded amount must equal 18 out of 30; since 12 are already shaded, 6 more whole squares must be fully shaded, so (q) is True.
Unshaded fraction = 18/30 = 3/5. Difference between unshaded and shaded = 3/5 − 2/5 = 1/5, not 2/5 — so (r) is False.
35
place-value
medium
Fill in the blanks and select the CORRECT option.
(p) The smallest 4-digit odd number that can be formed by using the digits 4, 8, 0 and 5 (each digit only once) is ____.
(q) There are ____ numbers that lie between 201 and 400, whose ones place digit is 0.
A
(p) 4085, (q) 19
B
(p) 4058, (q) 17
C
(p) 4805, (q) 19
D
(p) 4085, (q) 21
Show answer
Answer: A
(p) For the number to be odd, the last digit must be odd — only 5 qualifies among 4, 8, 0, 5. To make the number smallest, arrange the remaining digits (4, 8, 0) in ascending order with no leading zero: 4, 0, 8. This gives 4085.
(q) Numbers between 201 and 400 ending in 0 are 210, 220, 230, ..., 390 — that is (390 − 210) ÷ 10 + 1 = 19 numbers.